Jaringan Komputer

JARINGAN KOMPUTER

Tugas 1. Buat Jaringan Komputer seperti gambar di bawah dengan Aplikasi Packet Tracer.

     

 Dengan konfigurasi IP 

1. Subnet IP Address 172.16.X.0 /20, X adalah no urut absen Mahasiswa
2. Masukan Alamat Host IP subnet (network) 1 pada PC0 sampai PC4
3.  Masukan Alamat Host IP subnet (network) 2 pada PC5 sampai PC8

Network 1

1. IP PC0 = 172.16.9.1/20

Subnet = 255.255.240.0

2. IP PC1 = 172.16.9.2/20

Subnet = 255.255.240.0

3. IP PC3 = 172.16.9.3/20

Subnet = 255.255.240.0

4. IP PC4 = 172.16.9.4/20

 Subnet = 255.255.240.0

          

Network 2

1. IP PC5 = 172.16.17.1/20

Subnet = 255.255.240.0

2. IP PC6 = 172.16.17.2/20

Subnet = 255.255.240.0

3. IP PC7 = 172.16.17.3/20

Subnet = 255.255.240.0

4. IP PC8 = 172.16.17.4/20

Subnet = 255.255.240.0

Subneting /20 = 255. 255.240.0

11111111.11111111.11110000.00000000

Network           : 2⁴  = 16

Host                  : 2¹² - 2 = 4094

Blok Subnet      : 256 - 240 = 16

Net ID	Host ID		BC
	awal	akhir
172.16.0.0	172.16.0.1	172.16.15.254	172.16.15.255
172.16.16.0	172.16.16.1	172.16.31.254	172.16.31.255
172.16.32.0	172.16.32.1	172.16.47.254	172.16.47.255
172.16.48.0	172.16.48.1	172.16.63.254	172.16.63.255
172.16.64.0	172.16.64.1	172.16.79.254	172.16.79.255
172.16.80.0	172.16.80.1	172.16.95.254	172.16.95.255
172.16.96.0	172.16.96.1	172.16.111.254	172.16.111.255
172.16.112.0	172.16.112.1	172.16.127.254	172.16.127.255
172.16.128.0	172.16.128.1	172.16.143.254	172.16.143.255
172.16.144.0	172.16.144.1	172.16.159.254	172.16.159.255
172.16.160.0	172.16.160.1	172.16.175.254	172.16.175.255
172.16.176.0	172.16.176.1	172.16.191.254	172.16.191.255
172.16.192.0	172.16.192.1	172.16.207.254	172.16.207.255
172.16.208.0	172.16.208.1	172.16.223.254	172.16.223.255
172.16.224.0	172.16.224.1	172.16.239.254	172.16.239.255
172.16.240.0	172.16.240.1	172.16.255.254	172.16.255.255

Tugas 2.  Buat Jaringan Komputer seperti gambar di bawah dengan Aplikasi Packet Tracer.

   

Dengan konfigurasi IP  

1. Hitunglah Subnet IP address 10.0.X.0 /16, X adalah no urut absen Mahasiswa
2. Masukan Alamat Host IP subnet (network) 1 pada PC0 sampai PC3 serta Server0
3.  Masukan Alamat Host IP subnet (network) 4 pada PC5 sampai PC8 serta Server 1

Network 1

1. IP PC0 = 10.0.9.2/16

Subnet = 255.255.0.0

2. IP PC1 = 10.0.9.3/16

Subnet = 255.255.0.0

3. IP PC2 = 10.0.9.4/16

Subnet = 255.255.0.0

4. IP PC3 = 10.0.9.5/16

Subnet = 255.255.0.0

5. IP Server0 = 10.0.9.1

Subnet = 255.255.0.0

Network 4

1. IP PC5 = 10.3.9.2/16

Subnet = 255.255.0.0

2. IP PC6 = 10.3.9.3/16

Subnet = 255.255.0.0

3. IP PC7 = 10.3.9.4/16

Subnet = 255.255.0.0

4. IP PC8 = 10.3.9.5/16

Subnet = 255.255.0.0

5. IP Server1 = 10.3.9.1

Subnet = 255.255.0.0

Subneting /16 = 255.255.0.0

 111111111.11111111.00000000.00000000

Network = 2⁸ = 256

Host = 2¹⁶ - 2 = 65534

Blok Subnet = 256 - 255 = 1

Net ID	Host ID		BC
	Awal	Akhir
10.0.0.0	10.0.0.1	10.0.255.254	10.0.255.255
10.1.0.0	10.1.0.1	10.1.255.254	10.1.255.255
10.2.0.0	10.2.0.1	10.2.255.254	10.2.255.255
10.3.0.0	10.3.0.1	10.3.255.254	10.3.255.255
10.4.0.0	10.4.0.1	10.4.255.254	10.4.255.255
10.5.0.0	10.5.0.1	10.5.255.254	10.5.255.255
... sampai ...
10.255.0.0	10.255.0.1	10.255.255.254	10.255.255.255

 Untuk lebih jelasnya bisa download file paket tracer di bawah ini :

Tugas 1
Tugas 2